Town of Alfred, New York
Town of Alfred: a city in Allegany County, New York.
About
Town of Alfred is a place located in the county of Allegany in the U.S. state of New York.
Quick Facts about Town of Alfred
| State | New York (United States) |
| County | Allegany County |
| Latitude & Longitude | 42.2386,-77.7891 |
| Time Zone | America/New_York |
| Local time | 00:30:11 (7th November 2026) |
Geography
Town of Alfred is located at 42°14'19"N 77°47'21"W (42.2385700, -77.7890900).
Town of Alfred map
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Other cities in Allegany County
Cities, towns, neighborhoods & other populated places in Allegany County , NY.
| City Name | Population | Title |
|---|---|---|
| Alfred | 4,909 | Town in New York |
| Wellsville | 3,821 | City in Cache County, Utah |
| Marshall | 2,109 | Town in the U. |
| Cuba | 1,589 | Town in New York |
| Belfast | 1,557 | Town in New York, United States |