How far is Bloomington, IN from Clayton, IN?
The driving distance from Bloomington, IN to Clayton, IN is about 41.6 miles (66.9 km), with a travel time of about 01h 01m by car.
- The straight-line flight distance is about 36.2 miles (58.3 km).
- For a round trip, plan for roughly 02h 03m of driving time before adding stops, traffic, or weather delays.
- A comfortable departure window is usually 8:00 AM to 10:00 AM EDT.
Reverse, save, or send this route
This route works well as a day trip with time at the destination. Copy the route link, send it to another device, or print a clean version before you head out.
This route works well as a day trip with time at the destination.
Flight Distance
Driving Distance
Gas Cost Calculator
Leave and Arrive Planner
Pick a departure time to see your estimated arrival and same-day return window.
Drive time stays fixed at 01h 01m.
A morning start gives you useful time at the destination and keeps the return out of the late evening.
You are leaving earlier than the recommended window, which gives you extra margin for breaks and traffic.
Halfway Point
A useful midpoint for breaks, coffee, or meeting in the middle.
City in Morgan County, Indiana
Route Weather Snapshot
Check the forecast at both ends before you head out.
Mostly Sunny
Mostly Sunny
Driving Route Map
The map below follows the saved road route between Bloomington and Clayton.
Turn-by-Turn Driving Directions
Step-by-step road directions between Bloomington and Clayton.
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1
Start on the route
30 m · 11 sec
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2
Turn right onto South Indiana Avenue
1083 ft · 39 sec · South Indiana Avenue
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3
Turn left onto East 7th Street
1881 ft · 1 min · East 7th Street
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4
Turn right onto North Walnut Street
4.4 mi · 7 min · North Walnut Street
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5
Take the ramp straight
1834 ft · 45 sec
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6
Merge slight left
12.7 mi · 14 min
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7
Take the exit slight right toward SR 39 North: Martinsville
2253 ft · 49 sec
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8
Enter the roundabout and take exit 2 toward Morton Avenue
32 m · 2 sec · Morton Avenue
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9
Exit the roundabout onto Morton Avenue
647 ft · 13 sec · Morton Avenue
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10
Enter the roundabout and take exit 1 toward Morton Avenue
36 m · 3 sec · Morton Avenue
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11
Exit the roundabout onto Morton Avenue
1 mi · 2 min · Morton Avenue
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12
Turn left onto State Road 39
1.8 mi · 3 min · State Road 39
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13
Continue straight
3.4 mi · 4 min
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14
Turn left
7.7 mi · 11 min
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15
Turn right
47 m · 8 sec
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16
Turn left onto North Chestnut Street
2675 ft · 1 min · North Chestnut Street
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17
Continue on SR 39
6.4 mi · 12 min · SR 39
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18
Turn slight left onto Market Street
2.1 mi · 3 min · Market Street
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19
Turn right
23 m · 5 sec
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20
Arrive at your destination
0 m · 1 sec
Car Route Details
A richer read on the saved driving route between Bloomington and Clayton.
Turn-heavy local drive
The route has frequent decision points for its length, so lane choice and turn timing will matter more than cruising speed.
North Walnut Street
Merge slight left
12.7 mi · 00h 14m
Route Summary
A quick read on whether this route feels easy, ambitious, or worth planning around.
A comfortable day-trip route
This route works well as a day trip. You can leave in the morning, spend meaningful time at the destination, and still return the same day.
Mostly Sunny leaving Bloomington and Mostly Sunny near Clayton.
Trip Questions
Direct answers travelers usually want before committing to the drive.
How long does it take to drive from Bloomington to Clayton?
The road trip is about 41.6 miles (66.9 km) and usually takes 01h 01m in normal driving conditions.
Is this a same-day trip or an overnight route?
This route works well as a day trip. You can leave in the morning, spend meaningful time at the destination, and still return the same day.
What is the halfway point on this route?
Martinsville is a useful midpoint, sitting about 20.8 miles from Bloomington and 20.8 miles from Clayton.
How much longer is the road route than the straight-line distance?
The direct path is about 36.2 miles (58.3 km), while the road route adds roughly 5.4 extra miles because roads do not follow the straight air line.
When is the best time to leave for this route?
A good departure window is usually 8:00 AM to 10:00 AM EDT. If you want a more comfortable same-day return, try to leave by 4:26 PM EDT.
How much will gas cost for this route?
Using about 28.3 MPG, regular gas is estimated at $5.54 one way or $11.09 round trip. Estimated CO2 is about 13.1 kg one way.
What should you check before leaving?
Before you leave, expect Mostly Sunny around Bloomington and Mostly Sunny near Clayton.
Stop Ideas Near Martinsville
Useful break, food, and waypoint ideas within about 15 miles of the route midpoint.
Transit and Meeting Points
Useful pickup, handoff, or rendezvous points close to Martinsville.
Indianapolis Union Station
Crawfordsville
Crawfordsville (Bus), Indiana
Connersville station
Flight Path Map
This map shows the direct air route between Bloomington and Clayton. Straight-line distance: 36.19 mi (58.25 km).
#1 Bloomington
The most populous city in Monroe County, Indiana.
| Population | 85,603 |
| Coordinates | 39.1653300, -86.5263900 |
| Altitude | 235 |
| Country | United States |
#2 Clayton
Town in Indiana, United States
| Population | 1,032 |
| Coordinates | 39.6892100, -86.5225000 |
| Altitude | 267 |
| Country | United States |
End: Clayton (-86.5225, 39.68921)
Estimated Travel Time
Distance: 67 km by road
| Speed | Time |
|---|---|
| 30 mph (48.3 km/h) | 01h 23m |
| 40 mph (64.37 km/h) | 01h 02m |
| 50 mph (80.47 km/h) | 00h 49m |
| 60 mph (96.56 km/h) | 00h 41m |
| 70 mph (112.65 km/h) | 00h 35m |
| 80 mph (129 km/h) | 00h 31m |
Fuel, Round Trip and CO2
Estimated fuel cost and emissions for this route.
| Fuel | $/gal | One way | Round trip |
|---|---|---|---|
| Regular gas | $3.77 | $5.54 | $11.09 |
| Mid-grade | $4.25 | $6.25 | $12.50 |
| Premium | $4.65 | $6.84 | $13.68 |
| Diesel | $5.30 | $7.80 | $15.59 |
Assumes 8.3 L/100 km (about 28.3 MPG). CO2 is an estimate and varies by vehicle, fuel blend, traffic, and terrain.
Prices in Indiana · May 02, 2026
Distance to Other Cities
Planning a road trip? See the full trip guide on Trip.ovh — stops, fuel costs, weather, and departure timing.